(4x+3)(3x^2+3x+1)=

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Solution for (4x+3)(3x^2+3x+1)= equation:


Simplifying
(4x + 3)(3x2 + 3x + 1) = 0

Reorder the terms:
(3 + 4x)(3x2 + 3x + 1) = 0

Reorder the terms:
(3 + 4x)(1 + 3x + 3x2) = 0

Multiply (3 + 4x) * (1 + 3x + 3x2)
(3(1 + 3x + 3x2) + 4x * (1 + 3x + 3x2)) = 0
((1 * 3 + 3x * 3 + 3x2 * 3) + 4x * (1 + 3x + 3x2)) = 0
((3 + 9x + 9x2) + 4x * (1 + 3x + 3x2)) = 0
(3 + 9x + 9x2 + (1 * 4x + 3x * 4x + 3x2 * 4x)) = 0
(3 + 9x + 9x2 + (4x + 12x2 + 12x3)) = 0

Reorder the terms:
(3 + 9x + 4x + 9x2 + 12x2 + 12x3) = 0

Combine like terms: 9x + 4x = 13x
(3 + 13x + 9x2 + 12x2 + 12x3) = 0

Combine like terms: 9x2 + 12x2 = 21x2
(3 + 13x + 21x2 + 12x3) = 0

Solving
3 + 13x + 21x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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